What is the total volume of the stock solution?

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Subject: Uncategorized

The stock solution in the stock beaker contains 10.00 mL of 0.1000 M iron(III) nitrate solution, 10.00 mL of 0.1000 M potassium thiocyanate solution, and 10.00 mL of 0.5000 M nitric acid solution.

What is the total volume of the stock solution? SHOW YOUR WORK!

How many moles of iron (III) nitrate are present in the stock solution? SHOW YOUR WORK!

How many moles of potassium thiocyanate are present in the stock solution? SHOW YOUR WORK!

Based on the moles of iron (III) nitrate and moles of potassium thiocyanate, how many moles of iron (III) thiocyanate do you expect to be formed (Hint: think limiting reagent)? We can do it this time because we have enough of one reagent to force the reaction to completion. SHOW YOUR WORK!

Once you determine the moles of iron (III) thiocyanate formed, determine the concentration of iron (III) thiocyanate in the final solution. SHOW YOUR WORK!

1) What is the concentration of iron (III) thiocyanate in solution 2 that contains 10.00 mL of stock solution, labeled “Solution 1” (you just calculated the concentration of this solution in phase 1) and 40.00 mL of nitric acid solution? SHOW YOUR WORK!

2) What is the concentration of iron (III) thiocyanate in solution 3 containing 10.00 mL of solution 2 (you just calculated the concentration of this solution in phase 2 question 1) and 40.00 mL of nitric acid solution? SHOW YOUR WORK!

3) What is the concentration of iron (III) thiocyanate in solution 4 containing 10.00 mL of solution 3 (you just calculated the concentration of this solution in phase 2 question 2) and 40.00 mL of nitric acid solution? SHOW YOUR WORK!

1) Solution 1 contains 10.00 mL of 0.002 M iron (III) nitrate solution, 4.00 mL of 0.002 M potassium thiocyanate solution, and 6.00 mL of 0.05 M nitric acid solution.

a) Calculate the concentration of iron (III) nitrate in the final solution in Solution 1. SHOW ALL WORK!

b) Calculate the concentration of potassium thiocyanate in the final solution in Solution 1.

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